Question

46. Solve the quadratic equation ax2+bx+c=0 (a=0) by perfect square method.​

Answer 1

Answer:

x = 0, x =

Given

ax² - bx = 0 ← factor out x from each term

x(ax - b) = 0 ← in factored form

Equate each factor to zero and solve for x

x = 0

ax - b = 0 ⇒ ax = b ⇒ x =

Step-by-step explanation:

Hope this helps:)  ジョセフ

Answer 2

Answer:

x = [-b  ± √[(b^2 - 4ac]/2a.

Step-by-step explanation:

I think you mean a ≠ 0.

ax2+bx+c=0

Divide by a:

x^2 + (b/a)x + c/a = 0

(x + b/2a)^2 - b^2/4a^2 = -c/a

(x + b/2a)^2 = b^2/4a^2 - c/a

(x + b/2a)^2 =  (b^2 - 4ac)/4a^2

Taking square roots of both sides:-

x + b/2a =  ±√[(b^2 - 4ac)/4a^2]

x + b/2a =  ± √[(b^2 - 4ac)] / 2a

x = - b/2a ± √[(b^2 - 4ac)] / 2a

x = [-b  ± √[(b^2 - 4ac]/2a