Question

46. The position (x) of a body moving along a straight line at time t is given by x = (3t square – 5t + 2) m. Find
(0) Velocity at t = 2 s
(ii) Acceleration at t = 2 s and draw the corresponding velocity-time (v-t) and acceleration-time (a-t) graphs​

Answer 1

Answer:

When t=1, the velocity of the particle is 4+2=6 m/s.

When t=2, the velocity of the particle is 4+2×2=8 m/s.

After t seconds, the velocity of the particle is 4+2t m/s.

Explanation:

please mark me as brainlest plz