Question

46. Two water pipes P and Q having diameter 2 x10-2m
and 4 x10-2m respectively are joined in series with
the main supply line of water. The velocity of water
flowing in pipe Pis
(1) 4 times that of Q (2) 2 times that of Q
(3) times that of Q (4) a times that of Q​

Answer 1

The velocity of water  flowing in pipe P is 4 times that of Q.

Explanation:

Given data:

Diameter of P D(p) = 2 x 10^-2 m

Diameter of QD(q) = 4 x 10^-2 m

We need to calculate the velocity

Using Bernoulli theorem:

A1v1 = A2v2

Put the value into the formula.

π x (2 x 10^-2)^2 /4 x v1 = π x (  4 x 10^-2)^2 / 4 x v2

v1 / v2 = 4 /1

v1 = 4v2

Thus the velocity of water  flowing in pipe P is 4 times that of Q.

Also learn more

Determine the velocity of water at a point where the diameter is 4 cm when water flows through a horizontal pipe of varying cross section at the rate of 20 L per minute​ ?

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