Question

461+462+46+464461+462+46+464  is divisible by a prime number of two digits. Find the one tenth of the sum of digit​

Answer 1

Given  : 461+462+463+464  is divisible by a prime number of two digits.

To find : one tenth of the sum of digit​

Solution:

461 + 462 + 463 + 464

= 1850

1850 = 2 * 925

= 2 * 5 * 185

= 2  * 5 * 5 *  37

Prime number of two Digit is 37 here

Sum of Digit of 37 = 3 + 7 = 10

one tenth of the sum of digit​  = (1/10)10 = 1

1 is the  sum of digit​

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