Math, asked by kambohsarkaarofficia, 4 months ago

465x-75y=615 75x+465y=1005 solve by simultaneous eqaution​

Answers

Answered by HackerPaysBack
1

STEPS USING SUBSTITUTION

465x+75y=615

75x+465y=1005

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

465x+75y=615,75x+465y=1005

Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

465x+75y=615

Subtract 75y from both sides of the equation.

465x=−75y+615

Divide both sides by 465.

x=

465

1

(−75y+615)

Multiply

465

1

times −75y+615.

x=−

31

5

y+

31

41

Substitute

31

−5y+41

for x in the other equation, 75x+465y=1005.

75(−

31

5

y+

31

41

)+465y=1005

Multiply 75 times

31

−5y+41

.

31

375

y+

31

3075

+465y=1005

Add −

31

375y

to 465y.

31

14040

y+

31

3075

=1005

Subtract

31

3075

from both sides of the equation.

31

14040

y=

31

28080

Divide both sides of the equation by

31

14040

, which is the same as multiplying both sides by the reciprocal of the fraction.

y=2

Substitute 2 for y in x=−

31

5

y+

31

41

. Because the resulting equation contains only one variable, you can solve for x directly.

x=−

31

5

×2+

31

41

Multiply −

31

5

times 2.

x=

31

−10+41

Add

31

41

to −

31

10

by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

x=1

The system is now solved.

x=1,y=2

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