Math, asked by saleemamasood786, 1 month ago

46a7b2 is a number of 6 digits which a and b are two digits the number is divisible by 9 find at value of a+b also statement the maximum value a+b​

Answers

Answered by deepakkumar8022
0

we are given value are

46a7b2

and digit a+b are divided by 9 and find maximum value

then the value of a and b are 9

Answered by itzsecretagent
3

Answer:

we are given value are

46a7b2

and digit a+b are divided by 9 and find maximum value

then the value of a and b are 9

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