Question

46a7b2 is divisible by 9. What is maximum value of a+b

Answer 1

if 4+6+a+7+b+2 is divisible by 9 then only 46a7b2 will be divisible

to make it divisible a+b = 17

thus 4+6+a+7+b+2 becomes 36 which is divisible by 9