47. 0.0833 mol of carbohydrate of empirical formula
CH,O contain 1 g of hydrogen. The molecular
formula of carbohydrate is
(1) C5H1005
(2) Cg H,206
(3) C2H220,1
(4) C2H,02
48. How many moles of magnesium phosphate,
Mg3(PO4), will contain 0.25 mol of oxygen atoms?
(1) 3.125 * 10-2
(2) 1.25 x 10-2
(3) 2.5 * 10-2
(4) 0.125
Answers
Answer:
Explanation:
Molecular formula is a multiple of empirical formula. If the empirical formula is CH2O, then the molecular formula can be - n(CH2O) or, CnH2nOn.
As per the molecular formula, each mole of the carbohydrate contains n moles of carbon, 2n moles of hydrogen and n moles of oxygen.
Number of moles of carbohydrate = 0.0833 moles
Number of moles of hydrogen in this given amount = 2n x 0.0833 moles.
Since, the molar mass of hydrogen is 1 g/mol, Thus,
= 2n x 0.0833 mol x 1 g/mol = 1 g
Solving the equation, we will get, n = 6.
Thus, the molecular formula of the carbohydrate is C6H12O6 , that is the molecular formula of glucose.
1 mole of Mg3(PO4)2 contains 8 moles of - Oxygen
Thus, 8 moles of oxygen is contained by 1 mole of - Mg3(PO4)2.
0.25 moles of oxygen is contained by -
[ (0.25 × 1)/8 ]
= 25/ 800
= 0.03125 moles of Mg3(PO4)2.
= 3.125 × 10-2.
Answer:
Explanation:
Explanation:
Molecular formula is a multiple of empirical formula. If the empirical formula is CH2O, then the molecular formula can be - n(CH2O) or, CnH2nOn.
As per the molecular formula, each mole of the carbohydrate contains n moles of carbon, 2n moles of hydrogen and n moles of oxygen.
Number of moles of carbohydrate = 0.0833 moles
Number of moles of hydrogen in this given amount = 2n x 0.0833 moles.
Since, the molar mass of hydrogen is 1 g/mol, Thus,
= 2n x 0.0833 mol x 1 g/mol = 1 g
Solving the equation, we will get, n = 6.
Thus, the molecular formula of the carbohydrate is C6H12O6 , that is the molecular formula of glucose.
1 mole of Mg3(PO4)2 contains 8 moles of - Oxygen
Thus, 8 moles of oxygen is contained by 1 mole of - Mg3(PO4)2.
0.25 moles of oxygen is contained by -
[ (0.25 × 1)/8 ]
= 25/ 800
= 0.03125 moles of Mg3(PO4)2.
= 3.125 × 10-2.