Question

47. A and B together can do a piece of work in 10 days, but A alone can do it
in 15 days. How many days would B alone take to do the same piece of
work.​

Answer 1

Step-by-step explanation:

A and B can do a piece of work in 10 days.

Therefore A and B together can do 1/10 of work in one day.

A + B = 1/10…Eq..1

A alone can complete this work in 15 days. Thus A alone can do this work in 1/15.

Substituting the value of work done by A in Eq..1

A + B = 1/10

1/15 + B = 1/10

B = 1/10 - 1/15

B = (3 - 2)/30

B = 1/30

Thus, B can accomplish 1/30 of work in one day.

Accordingly, B alone could complete this work in 30 days.

Answer • : B alone could complete this work in 30 days