Question

47. A can finish a piece of work in 48 days. He worked alone for 18 days and then B

joined him. Together they could finish the remaining work in 18 3/4 days. In how
many days can B alone finish the same piece of work ?
1) 90
2) 60
3) 75
4) 80
5) ​

Answer 1

A-48

A+B - 30

so TW =240

B - efficiency 3

B alone= 240/3 = 80

Answer 2

Concept Introduction: Basic arithmetic is the basic concept of Mathematics.

Given:

We have been Given: A alone can finish in

$48 \: days$

he worked for

$18 \: days$

and then B joined him. Both finished the remaining work in

$18 \times \frac{3}{4} = \frac{75}{4}$

To Find:

We have to Find: In how many days B can finish the work alone?

Solution:

According to the Problem, A works

$\frac{18}{48} = \frac{3}{8}$

remaining,

$1 - \frac{3}{8} = \frac{5}{8}$

therefore, next

$\frac{5}{8} = \frac{75}{4} \\ \frac{5 \times 4}{8 \times 75} = \frac{1}{30}$

therefore,

$240 \div 30 = 80 \: days$

Final Answer: B alone can finish the work in

$80 \: days$

#SPJ2