Question

47) A party of 6 is to be formed 10 men and 7
women so as to include 3 men and 3 women.
In how many ways the party can be formed if
two particular women refuse to join together
is?
(€)
a) 4200 b) 600
c) 3600
d) None​

Answer 1

Answer:

The 2 women who won’t join: just forget about them.

You are left with 10 men and 5 women.

Choose 3 men from the 10 men. It can be done in (103) ways which is 120.

Choose 3 women from the other 5 women. This can be done in (53) ways which evaluate to 10.

Since choosing men and women are independent, just multiply them to get final answer 1200.