47. A steel plant is capable of producing x tonnes per day of a low - grade steel and y tonnes
40-5x
per day of a high-grade steel , where y = If the fixed market price of low - grade steel
10-X
is half that of high-grade steel, then what should be optimal productions in low - grade steel
and high-grade steel in order to have maximum receipts. (OR)
Answers
Answer:
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Step-by-step explanation:
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Answer:
In summary, to maximize revenue, the steel plant should produce 150 tonnes per day of low-grade steel and zero tonnes per day of high-grade steel.
Explanation:
To find the optimal productions of low-grade and high-grade steel, we need to maximize the total revenue. Let's first determine the revenue function:
Revenue = (price of low-grade steel)(quantity of low-grade steel) + (price of high-grade steel)(quantity of high-grade steel)
Let p be the price of high-grade steel. Then the price of low-grade steel is 0.5p. We can now substitute the given expressions for x and y into the revenue function:
Revenue = (0.5p)(x) + (p)(40-5x)
Simplifying the expression:
Revenue = 40p - 1.5px
Now, we need to find the values of x and y that maximize the revenue, subject to the constraints given:
y = 40 - 5x (equation 1)
0.5p = price of low-grade steel
p = price of high-grade steel
We can substitute equation 1 into the revenue equation to eliminate y:
Revenue = (0.5p)(x) + (p)(40-5x)
Revenue = 20p - 0.5px
We can now rewrite the problem as:
Maximize 20p - 0.5px subject to x≥0 and p≥0
To solve this problem, we need to take partial derivatives with respect to x and p, and set them equal to zero:
∂(20p - 0.5px)/∂x = -0.5p = 0
∂(20p - 0.5px)/∂p = 20 - 0.5x = 0
Solving for p and x:
p = 0
x = 40
Since p = 0, the price of high-grade steel is zero, and we should only produce low-grade steel. Therefore, the optimal production of low-grade steel is 150 tonnes per day (when x=40, y=0), and the optimal production of high-grade steel is zero.
In summary, to maximize revenue, the steel plant should produce 150 tonnes per day of low-grade steel and zero tonnes per day of high-grade steel.
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