47) How many electron must be removed from the
I metal sphere of ladies 0.05 m, so that it acquires
a charge of 4 x 10-15 c ? What is the electric field at
appoint (i) on the surface of the Sphere ii) at a
point 0.04 m from the centre of the Sphere?
(ec=1.6X.1 Ö-19 C).
Answers
Answer:
Charge of each electron e=1.6×10^−19C
Charge of each electron e=1.6×10^−19CNumber of electrons removed from the sphere n=4×10^10
Charge of each electron e=1.6×10^−19CNumber of electrons removed from the sphere n=4×10^10Thus total charged removed from the sphere q=ne
Charge of each electron e=1.6×10^−19CNumber of electrons removed from the sphere n=4×10^10Thus total charged removed from the sphere q=ne∴ q=4×10^10×1.6×10^−19=6.4×10^−9C
Charge of each electron e=1.6×10^−19CNumber of electrons removed from the sphere n=4×10^10Thus total charged removed from the sphere q=ne∴ q=4×10^10×1.6×10^−19=6.4×10^−9C Distance of point from the center of sphere r=20cm=0.2m
Charge of each electron e=1.6×10^−19CNumber of electrons removed from the sphere n=4×10^10Thus total charged removed from the sphere q=ne∴ q=4×10^10×1.6×10^−19=6.4×10^−9C Distance of point from the center of sphere r=20cm=0.2mThus electric field at that point E=kq/r^2
Charge of each electron e=1.6×10^−19CNumber of electrons removed from the sphere n=4×10^10Thus total charged removed from the sphere q=ne∴ q=4×10^10×1.6×10^−19=6.4×10^−9C Distance of point from the center of sphere r=20cm=0.2mThus electric field at that point E=kq/r^2 where k=1/4πϵo1=9×10^9
Charge of each electron e=1.6×10^−19CNumber of electrons removed from the sphere n=4×10^10Thus total charged removed from the sphere q=ne∴ q=4×10^10×1.6×10^−19=6.4×10^−9C Distance of point from the center of sphere r=20cm=0.2mThus electric field at that point E=kq/r^2 where k=1/4πϵo1=9×10^9⟹ E=9×109×6.4×10^−9/ (0.2)^2=1440NC^-1
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