47.
In the diagram, PQ and QR are tangents to the circle centre O, at P and R
respectively. Find the value of x
R
Attachments:
Answers
Answered by
5
Answer:
55
Step-by-step explanation:
∠POR=180−50=130
0
∠PSR=
2
130
=65
0
Join 'S' and 'O', then we get
∠SRO=∠OSR=30
0
[since OR=OS=radius]
∠OSP=65−30=35
0
∠SPO=35
o
=∠OSP
[since OS=OP=radius]
∠OPT=90
0
[OP⊥TQ]
x
0
=∠SPT=90
0
−35
0
∴x
0
=55
0
Similar questions