Question

47. Number of oxygen atoms present in 22 g CO2 is
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Answer 1

Answer :

6.022 * 10^23 atoms of O2

Explanation:

Given that,

Wt. of CO2 = W2 = 22 g

Mol. Wt. of CO2 = M2 = 44 g/mol

Mol. Wt. of O2 = 32 g/mol

No. of O2 atoms = ?

Here,

1 mole of CO2 contains = 2 moles of Oxygen atom

44 g of CO2 contains = 2 moles of oxygen atom

1 g of CO2 contains = (2/44) moles of Oxygen atoms

22 g of CO2 contains = (2/44)*22 moles of oxygen atoms

Therefore,

No. moles of Oxygen atom = (2/44)*22

No. of moles of oxygen atom = 1 mole

No. of moles of oxygen atom = 1*6.022*10^23 atoms

= 6.022*10^23 atoms