Question

47 tan (A+B) = 13 and tan A=1 then find angleB​

Answer 1

Answer:

Given that tanA=1/2,tanB=1/3

tan(A+B)=

1−tanAtanB

tanA+tanB

=

1−(

2

1

)(

3

1

)

2

1

+

3

1

=

6

5

×

5

6

=1

∴tan(A+B)=1=tan45

∘

⇒A+B=45

∘

hope, this will help you

Answer 2

Answer:

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