Question

47. The ratio of n-factor of K, C120, and HCI in the
reaction is
K2Cr2O, + 14HCI → 2KCI + 2CTCI, + 3Cl2 + 7H20
(1) 1:14
(2) 14:1
(3) 1:1
(4) 6:1​

Answer 1

Answer:

4) 6:1 is ur answer.............. hope it will help you