Question

479xyz is divisible by 7 11 13 what is (y+z/x)​

Answer 1

The value of $\dfrac{y+z}{x}$ = 4

Step-by-step explanation:

We have,

479xyz = divisible by 7, 11 and 13

To find, the vaue of $\dfrac{y+z}{x}=?$

∴ LCM of 7, 11 and 13

= 7 × 11 × 13

= 1001

∴ 479xyz

Put x = 4, y = 7 and z = 9

= 479479 is diivisible by 7, 11 and 13.

∴ $\dfrac{y+z}{x}$

$=\dfrac{7+9}{4}$

$=\dfrac{16}{4} =4$

Hence, the value of $\dfrac{y+z}{x}$ = 4