Question

47g of impure Al2O3 is reduced eletrolytically to give aluminium and oxygen. Calculate the amount of aluminium produced.

Answer 1

Answer:

amount of Al = 18.8g

Explanation:

let the amount Al and O be in the ratio be 2:3

hence, the total of ratio = 5

so , amount of Al =( 2÷5)*47

= 18.8g

and amount of O = (total amount-amount of Aluminium)

= 28.2g