Question

47x + 31y = 63
31x + 47y = 15
find the values__​

Answer 1

47x+31y=63(eqn 1)

31x+47y=15(eqn 2)

adding both eqn,we get

78x+78y=78

dividing this eqn by 78,we get

x+y=1 (be it eqn 3)

subtracting eqn 1 and eqn 2,we get

16x-16y=48

dividing this eqn by 16, we get

x-y=3(be it eqn 4)

using elimination method for eqn 3and eqn4

x+y=1

x-y=3

2x=4

x=2

putting value of x in x+y=1,by solving we get

y=-(negative)1

therefore

x=2

y=-1

step by step explaination:

1. First you have to subtract both the numbers. You get an answer(1).

2. Then you add both of the given equations. You get another answer (2).

3. Now compare answers 1and 2.

You get the answer... ☺

Hope it helps...

Answer 2

Answer:

1 y= 63 × 47 = 2,992 l hope it is right