Math, asked by giselchis14, 1 year ago

(-48÷12)^2-[(-22)÷(-11)]^2-[(-2)^2]^3+(-3^0)^10-[2(-5)]^2

Answers

Answered by monishaborah666
0

(-48÷12)^2-[(-22)÷(-11)]^2-[(-2)^2]^3+(-3^0)^10-[2(-5)]^2

=(-4)^2-2^2-4^3+1^10-(-10)^2

=16-4-64+1-100

=12-63-100

=-51-100

=-151

Step-by-step explanation:HOPE YOU UNDERSTAND IT...☺

PLEASE MARK IT AS BRAINLIEST...

Answered by Anonymous
0

Answer:

49

Step-by-step explanation:

(-48÷12)^2 = (-4)^2 = 16

[(-22)÷(-11)]^2 = 2^2 = 4

[(-2)^2]^3 = (4)^3 = 64

(-3^0)^10 = (1)^10 =1

[2(-5)^2] = (-10)^2 =100

so final answer is

16 - 4 -64+1+100

= 49

thank u

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