(-48÷12)^2-[(-22)÷(-11)]^2-[(-2)^2]^3+(-3^0)^10-[2(-5)]^2
Answers
Answered by
0
(-48÷12)^2-[(-22)÷(-11)]^2-[(-2)^2]^3+(-3^0)^10-[2(-5)]^2
=(-4)^2-2^2-4^3+1^10-(-10)^2
=16-4-64+1-100
=12-63-100
=-51-100
=-151
Step-by-step explanation:HOPE YOU UNDERSTAND IT...☺
PLEASE MARK IT AS BRAINLIEST...
Answered by
0
Answer:
49
Step-by-step explanation:
(-48÷12)^2 = (-4)^2 = 16
[(-22)÷(-11)]^2 = 2^2 = 4
[(-2)^2]^3 = (4)^3 = 64
(-3^0)^10 = (1)^10 =1
[2(-5)^2] = (-10)^2 =100
so final answer is
16 - 4 -64+1+100
= 49
thank u
Similar questions
Math,
6 months ago
Social Sciences,
6 months ago
Music,
6 months ago
Science,
1 year ago
Social Sciences,
1 year ago
English,
1 year ago
Math,
1 year ago