Math, asked by DarshLL, 4 months ago

(48^2−21^2)/27 step by step using algebraic identity.

Answers

Answered by anonymous1204
0

Answer:

Step-by-step explanation:

(48^2−21^2)/27

using (a^2-b^2)=(a+b)(a-b) identity

((48+21)(48-21))/27

((69)(27))/27

the 27 in the numerator and the denominator gets cancelled, which gives 69

Ans=69

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