Math, asked by tasu6, 1 year ago

48 ,3423 ,5620 ,6951 ,? , 8023 find the number series​

Answers

Answered by sharonr
0

The missing number in the series 48 ,3423 ,5620 ,6951 ,? , 8023 is 7680

Solution:

Given, series is 48, 3423, 5620, 6951, ? , 8023.

We have to find the missing term in the given series.

When we observe clearly, we can write the above series as

48,48+15^{3}, 3423+13^{3}, 5620+11^{3}, ?, 8023

So, the series is obtained by adding the previous term with cube of corresponding odd number from series of 15, 13, 11 …….

So, the next term would be,

6951+9^{3}=7680

Hence, the missing term is 7680

Answered by harendrachoubay
0

The value of missing number is "7680".

Step-by-step explanation:

The given sequnce are:

48 ,3423 ,5620 ,6951 ,? , 8023

The pattern gollow,

x + 15^{2} ,x + 13^{2},x + 11^{2},....

3423=48+15^{3} =48+3375=3420

5620=3423+13^{3} =3423+2197=5620

6951=5620+11^{3} =5620+1331=6951

Similarly.

Missing number(?) =6951+9^{3} =6951+729=7680

Hence, the value of missing number is "7680".

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