CBSE BOARD X, asked by alimranalom524, 2 months ago

48.
ইয়াৰে
থকাৰ
49.
সমাধান কৰা ঃ 0.9 - (0.3 x 0.3)
(a) 0.001
(6) 5.6
(c) 9
(d) 10
যদি Bসংখ্যাটো Cতকৈ 10%কম হয় আৰু Cসংখ্যাটে
1s০ তকৈ 5% বেছি হয়, তেন্তেB =?
(a) 151.75
(6) 157.85
(c) 153.85
(d) 141.75​

Answers

Answered by FERBILE
0

hello

0.9 - (0.3 x 0.3) = 0.9 - 0.09 = 0.81

Therefore, the answer is (d) 10.

If the number B is reduced by 10% to become C, then C is 90% of B, or 0.9B. Similarly, if C is increased by 5% to become 1.05C, then 1.05C is 105% of C, or 1.05 times C.

Given that C is 1.05 times 1.0, or 1.05, we can write:

0.9B = 1.05C

Substituting C = 1.05, we get:

0.9B = 1.05 x 1.0

Simplifying, we get:

0.9B = 1.05

B = 1.05 / 0.9

B = 1.1666667

Rounding off to two decimal places, we get:

B = 1.17

Therefore, the answer is (b) 157.85.

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