Question

48÷6(3+1) solve the following

a (2)
b (24)

Answer 1

$\frac{48}{6} (3 + 1) \\ = \frac{48}{2} + \frac{48}{6} \\ = \frac{144 + 48}{6} = \frac{192}{6} = 32$

$\frac{48}{6} \times (3 + 1) \\ = \frac{48}{6} \times 4 = \frac{192}{6} = 32$

$48 \div 6(3 + 1) \\ = 48 \div 6 \times 4 \\ = 8 \times 4 = 32$

$48 \div 6(3 + 1) \\ = 8(3 + 1) \\ = 24 + 8 = 32$






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