Question

48. A 0.5 molal aqueous solution of sucrose contains 'a'
mole fraction of solute. Value of 'a' is​

Answer 1

Answer:

m=1000X/M(1-x)

Here

m=molality

M=solvent molecular weight

X=Mole fraction of solute

We have 1 mol solute dissolved in 1 mol water

1 mol solute in 18g water

Molality=$\frac{0.5*1000}{18(1-0.5)} =55.5mol$

Molality=55.5m