Question

48
A projectile launched upwards from ground has a range of 180 m and its time of flight is 10 s. The velocity (in ms-1) after 5 s from start is (angle of
projection with horizontal is e)​

Answer 1

Given :  A projectile launched upwards from ground has a range of 180 m and its time of flight is 10 s

To find :  The velocity (in ms-1) after 5 s from start

Solution:

Let say horizontal Velocity = Vcose

& Vertical Velocity = V sine

Time of flight is 10 secs

V Cose * 10  = 180 m

=>V Cose = 18 m  / s

At 5 secs ( half of flight time it would be a top )

Hence Vertical velocity becomes = 0

only Horizontal velocity

Hence  Velocity after 5 sec   = 18 m /s

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