Math, asked by jaanuu080829, 3 months ago

48 bananas were distributed between Seema, Geeta & Seeta in the ratio 3:5:4 Then how many bananas did Geeta get?​

Answers

Answered by shivendramishra0367
0

Answer:

3x+4x+4x=48

11x=48

x=48/11

x=4.72

Answered by dualadmire
0

Given:

Total number of bananas= 48

Ratio in which they are divided= 3:5:4

To find:

How many bananas did Geeta get?

Solution:

Let us assume that Seema get 3x bananas,

Geeta get 5x bananas

And Seeta get 4x bananas.

Since total number of bananas to be distributed = 48

Therefore 3x+ 5x +4x= 48

12x = 48

x = 4

Number of bananas that Geeta gets = 5x = 5*4 = 20

Therefore Geeta gets 20 bananas out of 48 bananas.

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