Question

48) Carboxylic acid can be prepared from:
a) Alcohol
b) Ester
c) Grignard's reagent
d) All​

Answer 1

(D) All is the correct answer!

Explanation :

1) Preparation from Alcohol :

$\underline{\boxed{\tt{\orange{RCH_2OH\:\underset{KMnO_4/K_2Cr_2O_7}{\xrightarrow{Oxidation}}\:RCOOH}}}}$

2) Preparation from Ester :

$\underline{\boxed{\tt{\purple{RCOOR'\:\underset{\Delta}{\xrightarrow{NaOH,H_3O^+}}\:RCOOH}}}}$

3) Preparation from Grignard's reagent :

$\underline{\boxed{\tt{\gray{RMgX\:\underset{dry\:ether}{\xrightarrow{CO_2(dry\:ice)}}\:RCOOH}}}}$

Additional Information :

• Compounds having -COOH group and general formula, CₙH₂ₙO₂.
• Classification : Carboxylic acids are classified as monocarboxylic acids and polycarboxylic acids depending upon number of carboxyl groups present in a molecule.
• Structure : In Carboxylic acids, the bonds to the carboxyl carbon lie in one plane and are separated by about 120°. The carboxylic carbon is less electrophilic than carbonyl carbon because of the possible resonance structure.

Answer 2

(D) All is the correct answer!

Explanation :

1) Preparation from Alcohol :

$\underline{\boxed{\tt{\orange{RCH_2OH\:\underset{KMnO_4/K_2Cr_2O_7}{\xrightarrow{Oxidation}}\:RCOOH}}}}$

2) Preparation from Ester :

$\underline{\boxed{\tt{\purple{RCOOR'\:\underset{\Delta}{\xrightarrow{NaOH,H_3O^+}}\:RCOOH}}}}$

3) Preparation from Grignard's reagent :

$\underline{\boxed{\tt{\gray{RMgX\:\underset{dry\:ether}{\xrightarrow{CO_2(dry\:ice)}}\:RCOOH}}}}$

Additional Information :

Compounds having -COOH group and general formula, CₙH₂ₙO₂.

Classification : Carboxylic acids are classified as monocarboxylic acids and polycarboxylic acids depending upon number of carboxyl groups present in a molecule.

Structure : In Carboxylic acids, the bonds to the carboxyl carbon lie in one plane and are separated by about 120°. The carboxylic carbon is less electrophilic than carbonyl carbon because of the possible resonance structure.