48. For every real number x, there is a positive integer n
such that
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Step-by-step explanation:
If x and y are arbitrary real numbers such that x<y, prove that there exists at least one rational number r satisfying x<r<y, and hence infinitely many. Solution: Since (y − x) > 0, by the Archimedean property, there exists a positive integer n such that n(y − x) > 1. ... Dividing by n, we get (m/n) ≤ x < (m + 1)/n < y.
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