Question

48 g of (o3) and 80gms of so3 are placed in a vessel. The mole ratio of O3 and SO3 is
A)4/5 : 1
B) 1:1
C) 5:3
D) 4:1

Answer 1

ans. B) 1:1

Explanation:

moles= given mass/ mol mass

FOR O3

given mass- 48g

mol mass-16x3=48

no of moles=48/48 =1

FOR SO3

given mass-80gm

mol mass- 80gm

moles= 80/80=1

mole ratio = o3 : so3

= 1:1