Question

48 grams methane and 16 grams helium are kept in a closed vessel at 27°C. Find mope fraction of each gas and partial pressure of each gas and total pressure of mixture.
Kindly provide a step by step solution.​

Answer 1

Answer:

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Explanation:

According to Dalton's Law of partial pressure

p

A

=χ

A

.P

total

where, p

A

= partial pressure of gas A in the mixture,

χ

A

= mole fraction of gas A =

Totalnumberofmolesofgasespresentinthemixture(n

total

)

Numberofmolesofgas

′

A

′

(n

A

)

P

total

=Total pressure of the mixture = 740 mm

Number of moles of gas A, n

A

=

Molarmassofgas

′

A

′

(M

A

)

massofgas

′

A

′

(m

A

)

Using, m

O

2

=16g,M

O

2

=32g/mol, m

N

2

=28g,M

N

2

=28g/mol and m

CH

4

=8g,M

CH

4

=16g/mol

Calculating number of moles of each gas, we get: n

O

2

=0.5mol,n

N

2

=1molandn

CH

4

=0.5mol

Partial pressure of Nitrogen is therefore,

p

N

2

=χ

N

2

P

total

=

0.5+1+0.5

1

×740mm

=370mm