Question

48. If the weight of metal oxide is xg containing y g of
oxygen, the equivalent weight of metal will be
8(y - x)
8x
(1) E=
у
(2) E=
Х
(3) E=
y
8
(4) E=
8(x - y)
Y у
11​

Answer 1

Answer:

(8/y)*(x-y) is the answer

Explanation:

metal oxide = x

oxygen = y

Implies metal = x-y

The equivalent weight of Oxygen = 8

Implies 8 grams of oxygen will react with (8/y)*(x-y) gram of metal