Question

48.
If x² + y2 - xy = 3 and y - x = 1, then find xy÷x^2+y^2
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Answer 1

Answer:

y-x = 1

squaring on both sides

x²+y²-2xy = 1

x²+y²-xy-xy = 1

3-xy=1

xy=2

∴x²+y² = 3+xy = 3+2 = 5

xy÷x²+y² = 2/5

Step-by-step explanation:

Answer 2

Answer:

2/5

Step-by-step explanation:

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