Question

48 litre of Glycerin is mixed with 144 litre Rose water. D litre of total mixture is taken out and 32 litre Glycerin and 48 litre Rose water are added in the mixture. The final mixture contains 30% Glycerin, find the quantity of the mixture that is taken out.

Answer 1

32 liters of the mixture is taken out.

Step-by-step explanation:

48 litre of Glycerin is mixed with 144 litre Rose water

total mixture = 48+144 = 192 liter

glycerin % = $\frac{48}{192} \times100$ = 25%

then rose water = (100-25)% = 75%

i.e rose water is 75%

in the final mixture glycerin = 30%

then rose water =(100-30)% = 70%

ratio of glycerin to rose water = 30:70 = 3:7

then

$\frac{48-D\times0.25+32}{144-D\times 0.75+48} = \frac{3}{7}$

7(48-D×0.25+32) = 3(144-D×0.75+48)

7 (80-0.25 D) = 3(192- 0.75 D)

560-1.75D = 576 - 2.25D

2.25D - 1.75D = 576-560

0.5D = 16

D= $\frac{16}{0.5}$

D= 32 liters

hence,

32 liters of the mixture is taken out.

#Learn more:

In 40 litres mixture of glycirine and water the ratio of glycerine and water is 3:1 the quantity of water added in mixture in order to make this ratio 2:1 is

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