Question

48. PCI, (g) – PCI, (g) + Cl2 (9)
In above reaction, at equilibrium condition mole
fraction of PCI, is 0.4 and mole fraction of Cl, is
0.3. Then find out mole fraction of PCI,
(1) 0.3 (2) 0.7 (3) 0.4 (4) 0.6

Answer 1

Answer:

since sum of mole fractions is equal to 1

so here let mole ftaction of PCl be x

then

.4+.3+x=1

x=.3

so option 1is correct