Question

48. Select the species which has maximum number of
lone pair on its central atom.
(1) XeF6
(3) ICI4-
(4) PO4-3
(2) SO3​

Answer 1

answer : option (3) ICl4-

using formula to find lone pairs,

Lone pair = {sum of Valence electrons + x -y - (n - 1) × 8}/2

where n is total number of atoms present in molecule.

x represents negative charge included in species

and y represents positive charge included in species

for XeF6 ⇒ lone pairs = (7 × 6 + 8 - 6 × 8)/2 = 1

for ICl4- ⇒lone pairs = (7 + 7 × 4 + 1 - 4 × 8)/2 = 2

for PO4³- ⇒lone pairs = (5 + 6 × 4 + 3 - 4 × 8)/2 = 0

for SO3 ⇒lone pairs = (6 + 6 × 3 - 3 × 8)/2 = 0

it is clear that maximum number of lone pairs on ICl4- species.

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