48 similar cells each of emf 1.5 V and internal resistance 2 ohm are used for sending current through a
resistance of 6 ohm. What will be the current if the cells are connected in the following way: (i) 6 rows and 8
cells in a row, (ii) 4 rows and 12 cells in a row.
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Emf of each cell (e) = 1.5V, internal resistance (r) = 2 ohm, external resistance (R) = 6 ohm.
(i) No. of cells in a row (n) = 8
No. of rows (m) = 6
So, current, I = mne/mR + nr = 6×8×1.5/6×6+8×2
= 72/52
= 1.385 A
(ii) No. of cells in a row (n) = 12
No. of rows (m) = 4
So, current, I = mne/mR+nr = 4×12×1.5/4×6+12×2
= 72/48
= 1.5 A
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