Question

48 sweets are to be distributed among three friends A,B and C in such a way that gets 5 sweets more then A and C gets 7 sweets more than A. Form a equation.​

Answer 1

Step-by-step explanation:

X+5+x+7+x= 48

3x+12 = 48

-12 +3x +12= 48- 12

3x /3= 36/3

X= 12

Therefore a gets 12 sweets, b gets 17 sweets and c gets 19 sweets.

Answer 2

$n + n + 5 + n + 7 = 48 \\ 3n \: + \: 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 48 \\ 3n \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 48 - 12 \\ n \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{36}{3} =12 \\ \\ \\ \\ the \: equation \: formed \: is : \\ n + n \: + 5 + n + 7 = 48 \\ \\ \\ \\ \\ (as \: obtained) \: \\ a\: would \: get \: 12.$

b would get 17 and c would get 19.