Math, asked by darkgamer69, 9 months ago


48 sweets are to be distributed among three friends A, B and C in such a way that B gets 5 sweets
more than A and C gets 7 sweets more than A. Form an equation​

Answers

Answered by IamVishalGohil
4

Step-by-step explanation:

  • Let's assume, A gets X sweets... Then,
  • B gets 5+X
  • C gets 7+X
  • A+B+C=48
  • (X)+(5+X)+(7+X)=48
  • X+5+X+7+X=48
  • 3X+12=48
  • 3X=48-12= 36
  • X= 36/3= 12
  • A got 12, B got 5+X= 17, C got 7+X= 19 Sweets
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