Question

48 sweets are to be distributed among three friends A B and cin such a way that B gets 5 sweets
more than A and C gets ? sweets more than A. Form an equation.(with statement)​

Answer 1

Answer:

X+5+x+7+x= 48

X+5+x+7+x= 483x+12 = 48

X+5+x+7+x= 483x+12 = 48-12 +3x +12= 48- 12

X+5+x+7+x= 483x+12 = 48-12 +3x +12= 48- 123x /3= 36/3

X+5+x+7+x= 483x+12 = 48-12 +3x +12= 48- 123x /3= 36/3X= 12

X+5+x+7+x= 483x+12 = 48-12 +3x +12= 48- 123x /3= 36/3X= 12Therefore a gets 12 sweets, b gets 17 sweets and c gets 19 sweets.

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