Question

48 sweets are to be distributed among three friends A, B and C in such a way

that B gets 5 sweets more than A and C gets 7 sweets more than A. Form an

equation.​

Answer 1

Answer:

B has 5 more than A, and C has 7 more than A.

C has the most sweets so we can create the equation:

x + x+5 + x+7 = 48

3x = 36

x = 12

A has 12, B has 17 and C has 19

Answer 2

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge\tt \sf \pink{ \underline { \underline {❥Aɴsᴡᴇʀ° ᭄}}}$

$\sf\pink { \underline { \underline{❥︎x + 5 + x + 7 + x = 48}}}$

$\tt \sf\red { \underline{ \underline{❥︎3x + 12 = 48}}}$

$\tt \sf \purple{ \underline{ \underline{❥︎ - 12 + 3x + 12 = 48 - 12}}}$

$\large\tt \orange{❥︎ \frac{3x}{3} = \frac{36}{3} \: }$

$\large\tt \sf \green{ \underline{ \underline{❥︎x = 12}}}$

$\tt { \underline{ \underline{❥︎therefore \: a \: gets \: 12 \: sweets }}}$

$\tt \sf{ \underline{ \underline{❥︎b \: gets \: 17 \: sweets}}}$

$\tt \sf{ \underline{ \underline{❥︎c \: gets \: 19 \: sweets}}}$