Math, asked by shahriaral, 1 year ago

48. The average annual income of 11 workers is Tk. 14,650 and two of the workers each made
Tk. 19,333 for the year, what is the average monthly income in tk of the remaining 9 workers?

Answers

Answered by sweety132805
3

Use calculator ......

11 × 14650..

=.............

......... - 19333

= 9 workers yearly payment....

9 workers yearly payment ÷ 12

= The final answer.....

Please mark my Answer as BRIANALIEST.......

Answered by windyyork
0

The average monthly income would be Rs. 1134.11.

Step-by-step explanation:

Since we have given that

Average annual income of 11 workers = Rs. 14650

Average annual income of 2 workers = Rs. 19333

We need to find the average monthly income for remaining 9 workers.

So, we will first find yearly average income for 9 workers.

According to question, it becomes,

\dfrac{\sum x}{11}=14650\\\\\dfrac{x_1+x_2+\sum_{x=3}^{11}}{11}=14650\\\\19333\times 2+\sum _{x=3}^{11}=14650\times 11\\\\\text{Sum of incomes of Remaining 9 workers }=161150-38666=122484\\\\\text{Average of remaining 9 workers}=\dfrac{122484}{9}=13609.33\\\\\text{Average monthly income of 9 workers }=\dfrac{13609.33}{12}=1134.11

Hence, the average monthly income would be Rs. 1134.11.

# learn more:

40% of the employees in a factory are workers. All the remaining employees are executives. The annual income of each worker is Rs. 390. The annual income of each executive is Rs. 420. What is the average annual income of all the employees in the factory together?

A.390

B.405

C.408

D.415

https://brainly.in/question/6837580

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