Question

48. The average of 6 consecutive integers is 9.5.
Find the approximate average of the squares of
these integers.
(a) 73
(b) 80
(C) 93
(d) 74
​

Answer 1

Answer:

let x be the first integer

Step-by-step explanation:

so (x+15)÷6=9.5

so x=42

now proceed accordingly

Answer 2

Answer:

93

Step-by-step explanation:

let the first number be x,

x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)/6=9.5

6x+15/6=9.5

6x+15=57

6x=42

x=7

7^2+8^2+9^2+10^2+11^2+12^2/6

=559/6

=93