Question

48.) The smallest number which when divided by 15, 20 or 35 has in each case 3 as remainder, is -
Oa) 417
Ob) 843
Oc) 423
Aglonap=
0016​

Answer 1

Answer:

Shalom!

423 is the correct answer as L.C.M. of 15,20 ad 35 is 420.

So required no.=420+3=425.

Then it leaves remainder 3 in each case.

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