Question

4800 become 6000 in 4 years at a certain rate of compound interest what will be the sum of sum after 12 year

Answer 1

R = 5.74% (approx) and
A= 9,375 (approx)

Answer 2

Answer:

Sum of Sum after 12 years is Rs. 9648

Step-by-step explanation:

We are given that,

P = Rs. 4800

A = Rs. 6000

T = 4 years compounded annually

⇒ n = 4

To find: Sum of Sum after 12 years.

Let R be the rate of interest.

Using compound Interest Formula, we get

$A=P(1+\frac{R}{100})^n$

$6000=4800(1+\frac{R}{100})^4$

$(\frac{100+R}{100})^4=\frac{60}{48}$

$\frac{100+R}{100}=(\frac{60}{48})^{\frac{1}{4}}$

$\frac{100+R}{100}=1.06$

100 + R = 106

R = 6 %

Now,

$A=4800(1+\frac{6}{100})^{12}$

$A=4800(\frac{100+6}{100})^{12}$

$A=4800\times2.01$

$A=9648$

Therefore, Sum of Sum after 12 years is Rs. 9648