Question

48³-30³-18³ evaluate using identity. please answer this question​

Answer 1

Answer:

Answer:

Given:-

Evaluate 48³-30³-18³

Solution:-

Here, we are noticing that this equation is in the form of a³ +b³ +c³

Here we will a³+b³+c³ = 3abc, alzebric identity.

Here,

a³ = 48³

b³ = -30³

c³ = -18³

⇒ a^{3}+b^{3} +c^{3} = 3abc.

⇒ (48)^3 - (30)^3 - (18)^3 = 3 × 48 × (-30) × (−18)

= 77760

Required Answer = 77760

Step-by-step explanation:

Explanation:-

Some Alzebric identity are :-

(a+b+c)²= a²+b²+c² +2ab+2bc+2ca

(a+b-c)²=a²+b²+c² +2ab-2bc-2ca

a² + b²=½ [(a+b)²+(a-b)²]

a³-b³=(a-b)³ +3ab(a-b)

Answer 2

Answer:

77760

Step-by-step explanation:

110592 - 27000 - 5832

77760

hope it help