Question

48g of mg contain the same number of atoms as 160g another mono atomic element the atomic mass of the element is​

Answer 1

Answer:

80u

Explanation:

Give mass of Mg =48g, Molecular mass of Mg = 24u and Avogadro number=6.022×10*23

The number of atoms= Give mass/molar mass×Avogadro number Therefore number of Mg atoms=48÷24×6.022×10*23

=2×6.022×10*23=12.044×10*2

According to question given monoatomic element contain same number of atom that means numbers of atom =12.044×10*23 and given mass=160g

According to formula= Number of atom= Given mass÷molecular mass×6.022×10*23

12.044×10*23= 160÷M×6.022×10*23

=12.044×10*23×M=160×6.044×10*23

M=80u

Answer 2

Answer:

80gm

Explanation:

molecular weight of mg = 48

no.of moles of mg=48/24 = 2 moles

2moles of mono atomic element =160gm

1mole of mono atomic element=160/2=80gm

hence, atomic mass of the element = 80gm