48x2-13x-1=0 solve by factorisation method
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3
Answer:
48X2-13X-1=0
48X2+3X-16X-1=0
3X[16X+1]-1[16X+1]
[16X-1] [16X+1]
EITHER
16X-1=0 16X+1=0
X=-1/ 16 OR X=1/3
Answered by
4
48x² – 13x – 1 = 0
48x² – 16x + 3x – 1 = 0
16x ( 3x – 1 ) + 1 ( 3x – 1 ) = 0
( 3x – 1 ) ( 16x + 1 ) = 0
since. product of two numbers is zero hence
3x – 1 = 0
3x = 1
x = 1/3
or
16x + 1 = 0
16x = – 1
x = –1 / 16
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