Question

49-2.8x+0.04x^2. Please answer this question

Answer 1

$\huge\boxed{\mathfrak{\fcolorbox{orange}{green}{Here\:is\:u\:r\:Ans\:mate}}}$

$= 49 - 2.8x + 0.04x {}^{2}$

$= 49 - \frac{14}{5} x + \frac{1}{25} x {}^{2}$

$= \frac{1}{25} \times (1225 - 70x + x {}^{2} )$

$= using \: \: this \: \: formula \:$

$= a {}^{2} - 2ab + b {}^{2} = (a - b) {}^{2}$

$= \frac{1}{25} \times (35 - x) {}^{2}$

Means.,

$= 0.04(35 - x) {}^{2}$

$\mathcal{\orange{\huge{\star \:madhura20}}}$

Answer 2

Answer:

= 49 - 2.8x + 0.04x {}^{2}=49−2.8x+0.04x

2

= 49 - \frac{14}{5} x + \frac{1}{25} x {}^{2}=49−

5

14

x+

25

1

x

2

= \frac{1}{25} \times (1225 - 70x + x {}^{2} )=

25

1

×(1225−70x+x

2

)

= using \: \: this \: \: formula \:=usingthisformula

= a {}^{2} - 2ab + b {}^{2} = (a - b) {}^{2}=a

2

−2ab+b

2

=(a−b)

2

= \frac{1}{25} \times (35 - x) {}^{2}=

25

1

×(35−x)

2

Means.,

= 0.04(35 - x) {}^{2}=0.04(35−x)

2